-3a^2=27a=3

Solution for -3a^2=27a=3 equation:

-3a^2=27a=3

We move all terms to the left:

-3a^2-(27a)=0

a = -3; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·(-3)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*-3}=\frac{0}{-6}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*-3}=\frac{54}{-6}
=-9
$